The intermolecular forces of attraction present in 2-chloropentane that makes it have a higher boiling point than pentane isa.dipole-dipole interationsb.hydrogen bondc.covalent bondsd.van der Waals forces
Question
The intermolecular forces of attraction present in 2-chloropentane that makes it have a higher boiling point than pentane isa.dipole-dipole interationsb.hydrogen bondc.covalent bondsd.van der Waals forces
Solution
The intermolecular forces of attraction present in 2-chloropentane that makes it have a higher boiling point than pentane are van der Waals forces.
Here's why:
a. Dipole-Dipole Interactions: These occur between polar molecules. However, 2-chloropentane is a nonpolar molecule, so this option is incorrect.
b. Hydrogen Bond: This is a special type of dipole-dipole interaction that occurs when a hydrogen atom bonded to a highly electronegative atom (like nitrogen, oxygen, or fluorine) is attracted to another electronegative atom in a different molecule. 2-chlorop
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