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Select the correct answerThe batting average of a cricket player for 64 innings is 62 runs. His highest score exceeds his lowest score by 180 runs. Excluding these two innings, the average of remaining innings becomes 60 runs. His highest score was?Options209180212214

Question

Select the correct answerThe batting average of a cricket player for 64 innings is 62 runs. His highest score exceeds his lowest score by 180 runs. Excluding these two innings, the average of remaining innings becomes 60 runs. His highest score was?Options209180212214

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Solution

The problem can be solved by using the formula for average and some logical reasoning. Here are the steps:

  1. The total runs scored in 64 innings is 64 * 62 = 3968 runs.
  2. The total runs scored in the remaining 62 innings is 62 * 60 = 3720 runs.
  3. Therefore, the total runs scored in the two innings (highest and lowest) is 3968 - 3720 = 248 runs.
  4. We know that the highest score exceeds the lowest score by 180 runs. Let's denote the lowest score as x. Therefore, the highest score is x + 180.
  5. So, we have x + (x + 180) = 248.
  6. Solving this equation gives x = 34. Therefore, the highest score is 34 + 180 = 214 runs.

So, the correct answer is 214.

This problem has been solved

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