A stack is implemented with an array of 'A [0..N - 1]' and a varlable 'pos'. The push and pop operations are defined by the following code.push(x) A[pos] ← X pos ← pos - 1end pushpop( ) pos ← pos + 1 return A[pos]end popWhich of the following will initialize an empty stack with capacity N for the above Implementation?Optionspos ← N−1pos ← 0pos ← −1pos
Question
A stack is implemented with an array of 'A [0..N - 1]' and a varlable 'pos'. The push and pop operations are defined by the following code.push(x) A[pos] ← X pos ← pos - 1end pushpop( ) pos ← pos + 1 return A[pos]end popWhich of the following will initialize an empty stack with capacity N for the above Implementation?Optionspos ← N−1pos ← 0pos ← −1pos
Solution
The correct option to initialize an empty stack with capacity N for the above implementation is "pos ← N−1".
Here's why:
In the given implementation, the 'push' operation decreases the 'pos' variable by 1 each time an element is added to the stack. This means that the 'pos' variable is pointing to the top of the stack.
So, to initialize an empty stack with capacity N, 'pos' should be set to N-1. This is because in an array with size N, the last index is N-1 (since array indices start from 0). So, setting 'pos' to N-1 means that the stack is empty and the top of the stack is at the end of the array, ready to accept elements.
The other options are incorrect because setting 'pos' to 0 or -1 would not correctly represent an empty stack in this implementation.
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