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Given an integer array arr and a mapping function fn, return a new array with a transformation applied to each element.The returned array should be created such that returnedArray[i] = fn(arr[i], i).Please solve it without the built-in Array.map method.

Question

Given an integer array arr and a mapping function fn, return a new array with a transformation applied to each element.The returned array should be created such that returnedArray[i] = fn(arr[i], i).Please solve it without the built-in Array.map method.

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Solution

Sure, here is a step by step solution in JavaScript:

  1. First, define the function that will transform the array. This function will take two parameters: the array to be transformed and the mapping function.
function transformArray(arr, fn) {
  1. Inside this function, initialize an empty array to store the transformed elements.
    var transformedArray = [];
  1. Then, use a for loop to iterate over each element in the input array.
    for (var i = 0; i < arr.length; i++) {
  1. Inside the loop, apply the mapping function to the current element and its index, and store the result in the transformed array.
        transformedArray[i] = fn(arr[i], i);
  1. Close the for loop.
    }
  1. After the loop, return the transformed array.
    return transformedArray;
  1. Finally, close the function definition.
}

So, the complete function looks like this:

function transformArray(arr, fn) {
    var transformedArray = [];
    for (var i = 0; i < arr.length; i++) {
        transformedArray[i] = fn(arr[i], i);
    }
    return transformedArray;
}

You can use this function by passing an array and a mapping function as arguments. For example:

var arr = [1, 2, 3, 4, 5];
var fn = function(x, i) { return x * i; };
console.log(transformArray(arr, fn));  // Outputs: [0, 2, 6, 12, 20]

This problem has been solved

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