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What is Δn for the reaction below:2H2O(l)  ⟶ 2H2(g)  + O2(g) Group of answer choices-11-33

Question

What is Δn for the reaction below:2H2O(l)  ⟶ 2H2(g)  + O2(g) Group of answer choices-11-33

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Solution

Δn is the change in the number of moles of gas in a chemical reaction. It is calculated as the number of moles of gaseous products minus the number of moles of gaseous reactants.

In the reaction 2H2O(l) ⟶ 2H2(g) + O2(g), the number of moles of gaseous products is 2 (for H2) + 1 (for O2) = 3.

Since there are no gaseous reactants (H2O is in liquid state), the number of moles of gaseous reactants is 0.

Therefore, Δn = 3 - 0 = 3.

This problem has been solved

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