In the CCM, for a Boost converter, increasing the switching period and also the inductance 10 times result in decreasing the inductor current ripple:Question 4Select one:a.100 times.b.10 times.c.the ripple current will not change.d.1/10 timese.1/100 times
Question
In the CCM, for a Boost converter, increasing the switching period and also the inductance 10 times result in decreasing the inductor current ripple:Question 4Select one:a.100 times.b.10 times.c.the ripple current will not change.d.1/10 timese.1/100 times
Solution
The inductor current ripple in a Boost converter in Continuous Conduction Mode (CCM) is given by the formula:
ΔIL = (Vout - Vin) * D * Ts / L
where:
- ΔIL is the inductor current ripple
- Vout is the output voltage
- Vin is the input voltage
- D is the duty cycle
- Ts is the switching period
- L is the inductance
From this formula, we can see that the inductor current ripple is inversely proportional to the inductance (L) and the switching period (Ts). This means that if we increase the inductance and the switching period by 10 times, the inductor current ripple will decrease by a factor of 10 * 10 = 100 times.
So, the correct answer is:
a. 100 times.
Similar Questions
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