The zeros of a quadratic function are 6 and -4. Which of these choices could be the function?

The zeros of a quadratic function are the solutions to the equation f(x) = 0. In other words, they are the x-values where the graph of the function intersects the x-axis.

Given that the zeros of the function are 6 and -4, we can write the function in the form of f(x) = a(x - r)(x - s), where r and s are the roots of the equation, and a is a non-zero constant.

Substituting the given zeros into the equation, we get:

f(x) = a(x - 6)(x - (-4)) = a(x - 6)(x + 4)

So, any function of the form f(x) = a(x - 6)(x + 4), where a is a non-zero constant, could be the function.

For example, if a = 1, the function could be f(x) = (x - 6)(x + 4). If a = -1, the function could be f(x) = -(x - 6)(x + 4), and so on.

Therefore, to determine which of the given choices could be the function, you would need to check if they can be written in the form f(x) = a(x - 6)(x + 4), where a is a non-zero constant.