Calculate the solution to these simultaneous equations using the elimination method: (1)(1)2𝑞−2𝑝2q−2p==1010 (2)(2)2𝑞+𝑝2q+p==11
Question
Calculate the solution to these simultaneous equations using the elimination method: (1)(1)2𝑞−2𝑝2q−2p==1010 (2)(2)2𝑞+𝑝2q+p==11
Solution
The equations you provided seem to be formatted incorrectly, but I'll assume you meant:
- 2q - 2p = 10
- 2q + p = 11
Here's how you can solve these equations using the elimination method:
Step 1: Arrange the equations so that like terms are vertically aligned:
2q - 2p = 10 2q + p = 11
Step 2: Add the two equations together to eliminate one of the variables:
(2q - 2p) + (2q + p) = 10 + 11 4q - p = 21
Step 3: Solve for the remaining variable:
p = 4q - 21
Step 4: Substitute p into one of the original equations:
2q + (4q - 21) = 11 6q - 21 = 11 6q = 32 q = 32 / 6 q = 16/3
Step 5: Substitute q = 16/3 into the equation p = 4q - 21 to find p:
p = 4*(16/3) - 21 p = 64/3 - 63/3 p = 1/3
So, the solution to the system of equations is q = 16/3 and p = 1/3.
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