The speed of B is 63.63% more than A. A and B walk 36 hr. & 55 hr. respectively. If A will move 48 km less than B. Find the total distance covered by both A and B?Options156 km112 km134 km182 km

To solve this problem, we need to first find the speed of A and B.

1. Let's assume the speed of A is x km/hr. According to the problem, the speed of B is 63.63% more than A. So, the speed of B is 1.6363x km/hr.

2. Now, we know that distance = speed * time. So, the distance covered by A = x * 36 and the distance covered by B = 1.6363x * 55.

3. According to the problem, A will move 48 km less than B. So, we can set up the equation: x * 36 + 48 = 1.6363x * 55.

4. Solving this equation for x, we get x = 2 km/hr. So, the speed of A is 2 km/hr and the speed of B is 1.6363 * 2 = 3.2726 km/hr.

5. Now, we can find the total distance covered by both A and B. The total distance = distance covered by A + distance covered by B = (2 * 36) + (3.2726 * 55) = 72 + 179.993 = 251.993 km.

So, the total distance covered by both A and B is approximately 252 km. However, this option is not available in the given options. There might be a mistake in the problem or the options.