40 One molecule of an addition polymer containing 2000 repeat units has an Mr of 112 000.The polymer molecule contains chiral centres.What is a possible monomer for this polymer?A CH 2=CHCH 3B CH 2=C(CH 3) 2C CH 2=CHCH 2CH3D CH 2=CHCH 2CH2CH3

The molecular mass (Mr) of the polymer is given as 112,000 and it is also given that there are 2000 repeat units in one molecule of the polymer.

First, we need to find the molecular mass of the repeating unit (monomer). We can do this by dividing the molecular mass of the polymer by the number of repeat units:

112,000 / 2000 = 56 g/mol

This is the molecular mass of the monomer.

Now, we need to match this molecular mass with one of the given options.

A) CH2=CHCH3: The molecular mass is 123 + 16 + 216 = 42 g/mol B) CH2=C(CH3)2: The molecular mass is 124 + 110 = 58 g/mol C) CH2=CHCH2CH3: The molecular mass is 124 + 18 + 216 = 56 g/mol D) CH2=CHCH2CH2CH3: The molecular mass is 125 + 110 + 2*16 = 70 g/mol

So, the possible monomer for this polymer is C) CH2=CHCH2CH3 because its molecular mass matches with the calculated molecular mass of the monomer.