Let's denote the marks in English as E, in Maths as M, and in History as H.

From the problem, we know that:

1) M = 3E (Amit got thrice as many marks in Maths as in English)

2) M/H = 4/3 (The proportion of his marks in Maths and History is 4:3)

3) M + E + H = 250 (His total marks in Maths, English and History are 250)

We can use these equations to solve for E.

First, let's express M and H in terms of E using the first and second equations:

M = 3E

H = 3M/4 = 3*(3E)/4 = 9E/4

Now, we can substitute M and H in terms of E into the third equation:

3E + E + 9E/4 = 250

Multiply all terms by 4 to get rid of the fraction:

12E + 4E + 9E = 1000

25E = 1000

E = 1000 / 25 = 40

So, Amit got 40 marks in English. The correct answer is 40.

Question

Let's denote the marks in English as E, in Maths as M, and in History as H.

From the problem, we know that:

1) M = 3E (Amit got thrice as many marks in Maths as in English)

2) M/H = 4/3 (The proportion of his marks in Maths and History is 4:3)

3) M + E + H = 250 (His total marks in Maths, English and History are 250)

We can use these equations to solve for E.

First, let's express M and H in terms of E using the first and second equations:

M = 3E

H = 3M/4 = 3*(3E)/4 = 9E/4

Now, we can substitute M and H in terms of E into the third equation:

3E + E + 9E/4 = 250

Multiply all terms by 4 to get rid of the fraction:

12E + 4E + 9E = 1000

25E = 1000

E = 1000 / 25 = 40

So, Amit got 40 marks in English. The correct answer is 40.

Knowee AI · Accepted Answer