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Calculate the solution to these simultaneous equations using the substitution method: (1)(1)4𝑚+3𝑛4m+3n==1919 (2)(2)𝑚m==𝑛−4n−4

Question

Calculate the solution to these simultaneous equations using the substitution method: (1)(1)4𝑚+3𝑛4m+3n==1919 (2)(2)𝑚m==𝑛−4n−4

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Solution

Sure, let's solve these equations step by step.

Given equations are:

(1) 4m + 3n = 19 (2) m = n - 4

Step 1: Substitute equation (2) into equation (1)

This gives us: 4(n - 4) + 3n = 19

Step 2: Simplify the equation

This gives us: 4n - 16 + 3n = 19

Step 3: Combine like terms

This gives us: 7n - 16 = 19

Step 4: Add 16 to both sides of the equation

This gives us: 7n = 35

Step 5: Divide both sides of the equation by 7

This gives us: n = 5

Step 6: Substitute n = 5 into equation (2)

This gives us: m = 5 - 4

Step 7: Simplify the equation

This gives us: m = 1

So, the solution to the system of equations is m = 1, n = 5.

This problem has been solved

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