In Year 2, there are three times as many seven-year-olds as there are eight-year-olds. If there are 60 students in the year in total, how many of them are seven-year-olds?
Question
In Year 2, there are three times as many seven-year-olds as there are eight-year-olds. If there are 60 students in the year in total, how many of them are seven-year-olds?
Solution
Let's denote the number of seven-year-olds as S and the number of eight-year-olds as E.
From the problem, we know two things:
- S = 3E (There are three times as many seven-year-olds as there are eight-year-olds)
- S + E = 60 (There are 60 students in total)
We can substitute the first equation into the second to solve for E:
3E + E = 60 4E = 60 E = 60 / 4 E = 15
Substitute E = 15 into the first equation:
S = 3 * 15 S = 45
So, there are 45 seven-year-olds and 15 eight-year-olds.
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