What is the output of the following C++ code?#include <iostream>using namespace std;int main() {    int x = 10;    int y = 20;    cout << (x++ + ++y) << endl;    return 0;}  *1 point303132Compiler error

The output of the given C++ code is 32.

Here's the step-by-step explanation:

1. The x++ operation is a post-increment operation. It means that the value of x will be used first and then incremented. So, x++ will be 10.

2. The ++y operation is a pre-increment operation. It means that the value of y will be incremented first and then used. So, ++y will be 21.

3. The expression (x++ + ++y) will be (10 + 21) which equals 31.

4. However, remember that x was post-incremented, so after its value was used, it was incremented by 1. So, the final value of x is now 11.

5. Therefore, the output of the code will be the value of x (which is now 11) plus the value of y (which is 21), which equals 32.