A vector has magnitude same as that of A→=3jˆ+4jˆ and is parallel to B→=4iˆ+3jˆ. The x and y components of this vector in first quadrant are x and 3 respectively where x=_____

The magnitude of vector A→ is calculated using the Pythagorean theorem as √((3)^2 + (4)^2) = 5.

Since the vector we are looking for is parallel to B→, it has the same direction as B→. The direction of B→ is given by the ratio of its components, which is 4/3 in this case.

The components of the vector we are looking for are proportional to the components of B→, with the proportionality constant being the ratio of their magnitudes. Since the magnitude of the vector we are looking for is 5 (same as A→), and the magnitude of B→ is √((4)^2 + (3)^2) = 5, the proportionality constant is 1.

Therefore, the x and y components of the vector we are looking for are 4 and 3 respectively. So, x = 4.