A 50 kg skater pushed by a friend accelerates 5 m/sec2. How much force did the friend apply?
Question
A 50 kg skater pushed by a friend accelerates 5 m/sec2. How much force did the friend apply?
Solution
To solve this problem, we can use Newton's second law of motion, which states that the force applied to an object is equal to its mass times its acceleration. The formula is:
F = m * a
where: F is the force, m is the mass of the object, and a is the acceleration of the object.
Given in the problem: m = 50 kg (mass of the skater) a = 5 m/sec^2 (acceleration of the skater)
Substitute these values into the formula:
F = 50 kg * 5 m/sec^2 = 250 N
So, the friend applied a force of 250 Newtons.
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