Write the following expression as a single complex number.(‐4 + 3i) – (5 + 2i)1 + 5i1 + i-9 + i-9 + 5i

The given expression is a bit unclear, but I'll try to break it down as best as I can.

Let's start with the first part: (‐4 + 3i) – (5 + 2i)

Step 1: Subtract the real parts and the imaginary parts separately.

= (-4 - 5) + (3i - 2i) = -9 + i

Now, let's move to the second part: 1 + 5i

This is already a single complex number, so no further simplification is needed.

The third part: 1 + i

This is also already a single complex number, so no further simplification is needed.

The fourth part: -9 + i

This is also already a single complex number, so no further simplification is needed.

The fifth part: -9 + 5i

This is also already a single complex number, so no further simplification is needed.

So, if you meant to add all these together, the final expression would be:

(-9 + i) + (1 + 5i) + (1 + i) + (-9 + i) + (-9 + 5i)

= -25 + 13i

So, the given expression as a single complex number is -25 + 13i.