In the figure given, D divides the side BC of a ΔABC in the ratio 3 : 5. The area of ΔABD equals to

ABCD is a parallelogram of area "S". E and F are the mid points of the sides AD and BC respectively. If G is any point on the line EF. then the area of ΔAGB is equal to

In the following figure, ΔABC is a right-angled triangle, such that:♦ AC = 25 cm♦ PT || AB and SR || BC(Note: The figure is not to scale.)Find the area of ΔPQR. Show your work.

Question No 48.In right ΔABC, where ∠C is the right angle, point D lies on side AB, and point E lies on side BC such that AC = CD, DE = EB, and the ratio AC : DE = 4 : 3. What is the ratio AD : DB?

3.In a parallelogram  ABCD, E  is the midpoint of  CD . Find the ratio between the area of  △ABE  and area of Parallelogram  ABCD .

In a land of triangular shape ∆ABC , a line DE intersects the sides AB and AC in such a way that AB : BD = AC : CE. If the area of the land shaped as ∆DBC is 10 sq. meters, what is the area of ∆BEC?