An object is moving in a circle of radius ‘r’.Calculate the distance and the displacementa. When it completes the half the circle.b. When it complete one fullcircle.[𝝅𝒓, 𝟐𝒓 , 𝟐𝝅𝒓, 𝟎].Q-2-- A particle moves 3m north, then 4m eastand finally 6m south. Calculate the distancetravelled and the displacement. [13m, 5m]Q-3 A particle is moving in a circle of diameter5m. Calculate the distance covered and thedisplacement when it completes threerevolution.[15𝝅, 𝟎]Q-4- The speed of a Bicycle is 1.5km/h.,findtime taken to cross the field of 10m inlength.[24s].Q-5 A car travels 30km at a uniform speed of40km/h and next 30km/h at a uniform speed of20km/h. find the average speed.[26.7km/h]Q-6 A Train travels at 60km/h for 0.52h, at30km/h for the next 0.4h and at 70m/h for thenext 0.71h. What is the average speed of therain [59.9km/h]Q-7 on a 120km track, a train travels the first30km at a uniform speed of 30km/h. How fastmust the train travel the next 90km so as toaverage 60km/h for the entire trip.[90km/h]Q-8 A train travels some distance with speed30km/h and returns with a speed of 45km/h.Calculate the average speed of thetrain.[36km/h]Q-9 A car travels along a straight line for a halftime with speed of 40km/h and the second halftime with speed of 60km/h. Find the averagespeed of the car.[50km/h].Q-10 A train 100m long moving on a straightlevel track passes a pole in 5s. Finda) The speed of the train.

Sure, let's answer these questions one by one:

Q1: a. When the object completes half the circle, the distance covered is the circumference of the half circle which is πr. The displacement is the diameter of the circle which is 2r. b. When the object completes one full circle, the distance covered is the circumference of the circle which is 2πr. The displacement is 0 because the object is back to its starting point.

Q2: The particle moves 3m north, then 4m east and finally 6m south. So, the total distance travelled is 3m + 4m + 6m = 13m. The displacement is the shortest distance from the starting point to the final point which is 5m.

Q3: The particle is moving in a circle of diameter 5m. So, the radius is 2.5m. When it completes three revolutions, the distance covered is 3 times the circumference of the circle which is 15π. The displacement is 0 because the particle is back to its starting point.

Q4: The speed of the bicycle is 1.5km/h which is equal to 1500m/3600s = 0.4167m/s. So, the time taken to cross the field of 10m in length is 10m / 0.4167m/s = 24s.

Q5: The total distance travelled by the car is 30km + 30km = 60km. The total time taken is 30km/40km/h + 30km/20km/h = 1.5h + 1.5h = 3h. So, the average speed is 60km / 3h = 20km/h.

Q6: The total distance travelled by the train is 60km/h * 0.52h + 30km/h * 0.4h + 70km/h * 0.71h = 31.2km + 12km + 49.7km = 92.9km. The total time taken is 0.52h + 0.4h + 0.71h = 1.63h. So, the average speed of the train is 92.9km / 1.63h = 57km/h.

Q7: The total distance of the track is 120km. The train travels the first 30km at a speed of 30km/h. So, the time taken is 30km / 30km/h = 1h. In order to average 60km/h for the entire trip, the total time taken should be 120km / 60km/h = 2h. So, the time left for the train to travel the next 90km is 2h - 1h = 1h. Therefore, the speed must be 90km / 1h = 90km/h.

Q8: The train travels some distance with speed 30km/h and returns with a speed of 45km/h. The average speed is 2 * (30km/h * 45km/h) / (30km/h + 45km/h) = 36km/h.

Q9: The car travels along a straight line for a half time with speed of 40km/h and the second half time with speed of 60km/h. So, the average speed is (40km/h + 60km/h) / 2 = 50km/h.

Q10: The train is 100m long and it passes a pole in 5s. So, the speed of the train is 100m / 5s = 20m/s.