What is wrong with the following code?int n = 5;int array[5];int i = 3;array[n] = i;While it is possible to access array[n], we are not supposed to as this is not the array anymoreThe array array is not entirely initializedIt is impossible to declare the variable array this wayNothing is wrongI don't know

What is wrong with the following code?int n = 5;int array[5];int i = 3;array[n] = i;

Analyze the following code and choose the correct answer.int[] arr = new int[5];arr = new int[6];The code has compile errors because the variable arr cannot be changed once it is assigned. The code has runtime errors because the variable arr cannot be changed once it is assigned.The code can compile and run fine. The second line assigns a new array to arr.The code has compile errors because we cannot assign a different size array to arr.

Which of the following is not a correct way to initialize an array?a.int n[ 5 ] = { 0, 7, 0, 3, 8, 2 };b.int n[] = { 0, 7, 0, 3, 8, 2 };c.int n[ 5 ] = { 7 };d.int n[ 5 ] = { 9, 1, 9 };

How is an array initialized in C language?int (a)=[1,2,3];int a[3]={1,2,3};int a[]=new int[3]int a={1,2,3};

Given the array declaration int arr[5] = {1, 2, 3};, what are the values of arr[3] and arr[4]?Both arr[3] and arr[4] are 0Both arr[3] and arr[4] are uninitializedarr[3] is 3 and arr[4] is 3arr[3] is 2 and arr[4] is 2