A father is 1 year older than 4 times his son's age. However, in 4 years time, he will only be three times older than his son. What is sum of their ages?A28B32C36D40E44
Question
A father is 1 year older than 4 times his son's age. However, in 4 years time, he will only be three times older than his son. What is sum of their ages?A28B32C36D40E44
Solution
Let's denote the son's current age as S and the father's current age as F.
From the problem, we have two equations:
-
F = 4S + 1 (since the father is 1 year older than 4 times his son's age)
-
F + 4 = 3(S + 4) (since in 4 years time, the father will be three times older than his son)
We can solve these equations step by step:
First, substitute equation 1) into equation 2):
4S + 1 + 4 = 3S + 12
Simplify the equation:
S = 7
Substitute S = 7 into equation 1) to find F:
F = 4*7 + 1 = 29
So, the son is 7 years old and the father is 29 years old.
The sum of their ages is 7 + 29 = 36.
So, the answer is C36.
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