To solve this problem, we need to set up a proportion using the given scale and the actual width of the garage.

The given scale is 8 millimeters : 3 meters. This means that 8 millimeters on the drawing represents 3 meters in real life.

We can set up the proportion as follows:

8 mm / 3 m = x mm / 9 m

To solve for x, which represents the width of the garage on the drawing, we cross-multiply:

8 mm * 9 m = 3 m * x mm

72 mm = 3x

Then, divide both sides by 3 to solve for x:

x = 72 mm / 3 = 24 mm

So, the width of the garage on the drawing is 24 millimeters.

Question

To solve this problem, we need to set up a proportion using the given scale and the actual width of the garage.

The given scale is 8 millimeters : 3 meters. This means that 8 millimeters on the drawing represents 3 meters in real life.

We can set up the proportion as follows:

8 mm / 3 m = x mm / 9 m

To solve for x, which represents the width of the garage on the drawing, we cross-multiply:

8 mm * 9 m = 3 m * x mm

72 mm = 3x

Then, divide both sides by 3 to solve for x:

x = 72 mm / 3 = 24 mm

So, the width of the garage on the drawing is 24 millimeters.

Knowee AI · Accepted Answer