The following chemical reaction takes place in aqueous solution:CuBr2(aq)+NH42S(aq)→CuS(s)+2NH4Br(aq)Write the net ionic equation for this reaction.
Question
The following chemical reaction takes place in aqueous solution:CuBr2(aq)+NH42S(aq)→CuS(s)+2NH4Br(aq)Write the net ionic equation for this reaction.
Solution
Sure, here are the steps to write the net ionic equation for the given reaction:
Step 1: Write the balanced molecular equation: CuBr2(aq) + (NH4)2S(aq) → CuS(s) + 2NH4Br(aq)
Step 2: Write the ionic equation. This involves breaking all the (aq) compounds into their ions: Cu2+(aq) + 2Br-(aq) + 2NH4+(aq) + S2-(aq) → CuS(s) + 2NH4+(aq) + 2Br-(aq)
Step 3: Write the net ionic equation. This involves removing the spectator ions, which are present on both sides of the equation. In this case, the spectator ions are 2NH4+ and 2Br-: Cu2+(aq) + S2-(aq) → CuS(s)
So, the net ionic equation for the given reaction is Cu2+(aq) + S2-(aq) → CuS(s).
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