The batting average of a cricketer for 78 innings is 38 runs.His highest score exceeds the lowest score by 226 runs.If these two innings are excluded, the average of the remaining innings is 36 runs.What is his hightest score?1502502273
Question
The batting average of a cricketer for 78 innings is 38 runs.His highest score exceeds the lowest score by 226 runs.If these two innings are excluded, the average of the remaining innings is 36 runs.What is his hightest score?1502502273
Solution
The total runs scored by the cricketer in 78 innings = 78 * 38 = 2964 runs.
When the highest and the lowest scores are excluded, the total runs scored in the remaining 76 innings = 76 * 36 = 2736 runs.
So, the sum of the highest and the lowest scores = 2964 - 2736 = 228 runs.
Given that the highest score exceeds the lowest score by 226 runs, let's denote the lowest score as x. Therefore, the highest score is x + 226.
So, x + (x + 226) = 228.
Solving this equation gives x = 1.
Therefore, the highest score is 1 + 226 = 227.
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