Knowee
Questions
Features
Study Tools

The electric field and initial velocity of the charged particle are inclined at angleChoose answer: 60° 30° 90° 150°

Question

The electric field and initial velocity of the charged particle are inclined at angleChoose answer: 60° 30° 90° 150°

🧐 Not the exact question you are looking for?Go ask a question

Solution

To determine the angle between the electric field and the initial velocity of the charged particle, we need to use trigonometry.

  1. First, identify the given angle options: 60°, 30°, 90°, 150°.
  2. Next, recall that the angle between two vectors can be found using the dot product formula: cosθ = (A · B) / (|A| |B|) where A and B are the vectors and θ is the angle between them.
  3. In this case, the electric field and initial velocity are the vectors. Let's assume the electric field vector is A and the initial velocity vector is B.
  4. Calculate the dot product of A and B: A · B.
  5. Calculate the magnitudes of A and B: |A| and |B|.
  6. Substitute the values into the dot product formula: cosθ = (A · B) / (|A| |B|).
  7. Calculate the value of cosθ using the given values of A · B, |A|, and |B|.
  8. Finally, determine the angle θ by taking the inverse cosine (cos⁻¹) of cosθ.
  9. Compare the calculated angle with the given options of 60°, 30°, 90°, 150° to find the correct answer.

This problem has been solved

Similar Questions

The electric field and initial velocity of the charged particle are inclined at angle

A positive charge is placed in an electric field that points south. What direction is the force on the positive particle?

In the figure provided, for the charged particle entering the magnetic field, what is the initial direction of deflection? Left Up Right Down

In what direction will a negatively charged particle accelerate in an electric field?Group of answer choicesIn the same direction as fieldIn opposite direction as fieldPerpendicular to fieldImpossible to tell

A particle with positive charge q = 2.08 10-18 C moves with a velocity v = (4î + 4ĵ − ) m/s through a region where both a uniform magnetic field and a uniform electric field exist.(a)Calculate the total force on the moving particle, taking B = (4î + 3ĵ + ) T and E = (3î − ĵ − 2) V/m. (Give your answers in N for each component.)Fx = NFy = NFz = N(b)What angle does the force vector make with the positive x-axis? (Give your answer in degrees counterclockwise from the +x-axis.) ° counterclockwise from the +x-axis(c)What If? For what vector electric field would the total force on the particle be zero? (Give your answers in V/m for each component.)Ex = V/mEy = V/mEz = V/m

1/3

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.