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Solve the system: x + y + z = 6, 2x – y + z = 3, x + y – z = 0Question 32Select one:a.(0, 0, 6)b.(3, 2, 1)c.(0, 0, 1)d.(1, 2, 3)e.None of these

Question

Solve the system: x + y + z = 6, 2x – y + z = 3, x + y – z = 0Question 32Select one:a.(0, 0, 6)b.(3, 2, 1)c.(0, 0, 1)d.(1, 2, 3)e.None of these

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Solution

To solve the system of equations, we can use the method of substitution or elimination. Here, we will use the elimination method.

The system of equations is:

  1. x + y + z = 6
  2. 2x - y + z = 3
  3. x + y - z = 0

First, let's subtract the third equation from the first to eliminate y and z:

      1. gives: x - x = 6 - 0, which simplifies to 0 = 6.

This is a contradiction, which means that the system of equations has no solution. Therefore, the correct answer is e. None of these.

This problem has been solved

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