Cost price of article A is Rs.X+150 and cost price of article B is Rs.X-150. Article A sold at loss of 20% and article B sold at profit of 25%. If the selling price of article B is Rs.750 more than that of article A. Find the cost price of B.
Question
Cost price of article A is Rs.X+150 and cost price of article B is Rs.X-150. Article A sold at loss of 20% and article B sold at profit of 25%. If the selling price of article B is Rs.750 more than that of article A. Find the cost price of B.
Solution
Let's solve the problem step by step:
- Let's assume the cost price of article A is Rs. X + 150.
- Similarly, let's assume the cost price of article B is Rs. X - 150.
- Article A is sold at a loss of 20%, which means it is sold for 80% of its cost price. So, the selling price of article A is 80% of (X + 150), which can be written as 0.8 * (X + 150).
- Article B is sold at a profit of 25%, which means it is sold for 125% of its cost price. So, the selling price of article B is 125% of (X - 150), which can be written as 1.25 * (X - 150).
- According to the given information, the selling price of article B is Rs. 750 more than that of article A. So, we can write the equation as: 1.25 * (X - 150) = 0.8 * (X + 150) + 750.
- Now, let's solve the equation to find the value of X, which represents the cost price of article B.
By simplifying the equation, we get: 1.25X - 187.5 = 0.8X + 120 + 750 1.25X - 0.8X = 870 + 187.5 - 120 0.45X = 937.5 X = 937.5 / 0.45 X ≈ 2083.33
Therefore, the cost price of article B is approximately Rs. 2083.33.
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