Here is a step-by-step solution to the problem:

1. First, we need to create a stack data structure. In many programming languages, this can be done using a list or array.

2. Next, we iterate over the input string. For each character in the string, we do the following:

- If the character is an opening bracket (i.e., '{', '[', or '('), we push it onto the stack.

- If the character is a closing bracket (i.e., '}', ']', or ')'), we check the top of the stack. If the top of the stack is the corresponding opening bracket, we pop it from the stack. If it's not, or if the stack is empty, we return "Not Balanced".

3. After we've processed all the characters in the string, we check if the stack is empty. If it is, we return "Balanced". If it's not, we return "Not Balanced".

Here is a pseudocode representation of the solution:

```
function isBalanced(expression):
stack = new Stack()

for char in expression:
if char in ['{', '[', '(']:
stack.push(char)
else:
if stack.isEmpty():
return "Not Balanced"
top = stack.pop()
if not matches(top, char):
return "Not Balanced"

if stack.isEmpty():
return "Balanced"
else:
return "Not Balanced"

function matches(open

Question

Here is a step-by-step solution to the problem:

1. First, we need to create a stack data structure. In many programming languages, this can be done using a list or array.

2. Next, we iterate over the input string. For each character in the string, we do the following:

- If the character is an opening bracket (i.e., '{', '[', or '('), we push it onto the stack.
   
   - If the character is a closing bracket (i.e., '}', ']', or ')'), we check the top of the stack. If the top of the stack is the corresponding opening bracket, we pop it from the stack. If it's not, or if the stack is empty, we return "Not Balanced".

3. After we've processed all the characters in the string, we check if the stack is empty. If it is, we return "Balanced". If it's not, we return "Not Balanced".

Here is a pseudocode representation of the solution:

```
function isBalanced(expression):
    stack = new Stack()
    
    for char in expression:
        if char in ['{', '[', '(']:
            stack.push(char)
        else:
            if stack.isEmpty():
                return "Not Balanced"
            top = stack.pop()
            if not matches(top, char):
                return "Not Balanced"
    
    if stack.isEmpty():
        return "Balanced"
    else:
        return "Not Balanced"

function matches(open

Knowee AI · Accepted Answer

Here is a step-by-step solution to the problem:

1. First, we need to create a stack data structure. In many programming languages, this can be done using a list or array.

2. Next, we iterate over the input string. For each character in the string, we do the following:

- If the character is an opening bracket (i.e., '{', '[', or '('), we push it onto the stack.
   
   - If the character is a closing bracket (i.e., '}', ']', or ')'), we check the top of the stack. If the top of the stack is the corresponding opening bracket, we pop it from the stack. If it's not, or if the stack is empty, we return "Not Balanced".

3. After we've processed all the characters in the string, we check if the stack is empty. If it is, we return "Balanced". If it's not, we return "Not Balanced".

Here is a pseudocode representation of the solution:

```
function isBalanced(expression):
    stack = new Stack()
    
    for char in expression:
        if char in ['{', '[', '(']:
            stack.push(char)
        else:
            if stack.isEmpty():
                return "Not Balanced"
            top = stack.pop()
            if not matches(top, char):
                return "Not Balanced"
    
    if stack.isEmpty():
        return "Balanced"
    else:
        return "Not Balanced"

function matches(open

Question

Solution

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