Rick O. Chey pulls the 50.0 kg box across the floor at a constant speed. He pulls on the rope with a force of 245 N as shown in the picture. Calculate the following:a) Normal force from the floor on the box.b) Friction force from the floor on the box.
Question
Rick O. Chey pulls the 50.0 kg box across the floor at a constant speed. He pulls on the rope with a force of 245 N as shown in the picture. Calculate the following:a) Normal force from the floor on the box.b) Friction force from the floor on the box.
Solution
To solve this problem, we need to understand a few basic principles of physics.
a) Normal force from the floor on the box:
The normal force is the force exerted by a surface that supports the weight of an object resting on it. It acts perpendicular (or "normal") to the surface. The normal force is equal to the weight of the object, so we can calculate it using the formula:
Normal Force = mass * gravity
where the mass is 50.0 kg and gravity is approximately 9.8 m/s².
Normal Force = 50.0 kg * 9.8 m/s² = 490 N
So, the normal force from the floor on the box is 490 N.
b) Friction force from the floor on the box:
The friction force can be calculated by subtracting the force exerted by Rick from the normal force. Since Rick is pulling the box at a constant speed, the friction force and the force exerted by Rick are equal in magnitude but opposite in direction.
Friction Force = Normal Force - Force exerted by Rick
Friction Force = 490 N - 245 N = 245 N
So, the friction force from the floor on the box is 245 N.
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