In a series LCR-circuit, if the capacitive and inductive reactance are 120 12 and 200 Q respectively and R is 60 2. So, the impedance of the circuit will be Α- 100 Ω Β- 120 Ω C- 200 Ω - D-250 Ω
Question
In a series LCR-circuit, if the capacitive and inductive reactance are 120 12 and 200 Q respectively and R is 60 2. So, the impedance of the circuit will be Α- 100 Ω Β- 120 Ω C- 200 Ω
- D-250 Ω
Solution
In an LCR series circuit, the impedance (Z) is calculated using the formula:
Z = sqrt[(R^2) + (XL - XC)^2]
where: R = resistance XL = inductive reactance XC = capacitive reactance
Given in the problem: R = 60 Ω XL = 200 Ω XC = 120 Ω
Substituting these values into the formula:
Z = sqrt[(60^2) + (200 - 120)^2] Z = sqrt[(3600) + (80)^2] Z = sqrt[(3600) + (6400)] Z = sqrt[10000] Z = 100 Ω
So, the impedance of the circuit is 100 Ω. Therefore, the correct answer is Α- 100 Ω.
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