Solve the system (domain is all real numbers): y = x2 + 5, y = x - 4Question 35Select one:a.(0, 5)b.(0, -4)c.(1, 6) and (1, -3)d.No solutione.None of these

To solve the system of equations, we need to set the two equations equal to each other because they both equal y.

So, we have:

x^2 + 5 = x - 4

To solve this equation, we need to move all terms to one side of the equation:

x^2 - x + 9 = 0

This is a quadratic equation in the form ax^2 + bx + c = 0. We can solve it using the quadratic formula x = [-b ± sqrt(b^2 - 4ac)] / (2a).

In this case, a = 1, b = -1, and c = 9.

Substituting these values into the quadratic formula gives:

x = [1 ± sqrt((1)^2 - 419)] / (2*1) x = [1 ± sqrt(1 - 36)] / 2 x = [1 ± sqrt(-35)] / 2

Since the square root of a negative number is not a real number, there are no real solutions to this equation.

So, the answer is (d) No solution.