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Becca plays a game in which she can purchase a ticket. Each ticket has several chances, or "catches," to win money.The table below shows the probability of winning at each stage, and how much money the ticket can win at each catch. Every time Becca plays the game, her ticket is played through each catch, which means she can win money at each stage.Catch Probability WinningsCatch 0 40% $1Catch 1 45% $5Catch 2 12% $10Catch 3 3% $25Given the probabilities and payout values in this table, what is the expected value of Becca's ticket?a.)$4.60b.)$1.20c.)$10.25d.)$41.00

Question

Becca plays a game in which she can purchase a ticket. Each ticket has several chances, or "catches," to win money.The table below shows the probability of winning at each stage, and how much money the ticket can win at each catch. Every time Becca plays the game, her ticket is played through each catch, which means she can win money at each stage.Catch Probability WinningsCatch 0 40% 1Catch1451Catch 1 45% 5Catch 2 12% 10Catch3310Catch 3 3% 25Given the probabilities and payout values in this table, what is the expected value of Becca's ticket?a.)4.60b.)4.60b.)1.20c.)10.25d.)10.25d.)41.00

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Solution

To calculate the expected value of Becca's ticket, we need to multiply the probability of each catch by the winnings of that catch, and then sum up these values.

For Catch 0, the expected value is 0.40 * 1=1 = 0.40 For Catch 1, the expected value is 0.45 * 5=5 = 2.25 For Catch 2, the expected value is 0.12 * 10=10 = 1.20 For Catch 3, the expected value is 0.03 * 25=25 = 0.75

Adding these up, we get 0.40+0.40 + 2.25 + 1.20+1.20 + 0.75 = $4.60

So, the expected value of Becca's ticket is 4.60,whichcorrespondstooptiona.)4.60, which corresponds to option a.) 4.60.

This problem has been solved

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