Solve for x:2, start superscript, 2, x, minus, 4, end superscript, equals, 8, to the power 42 2x−4 =8 4
Question
Solve for x:2, start superscript, 2, x, minus, 4, end superscript, equals, 8, to the power 42 2x−4 =8 4
Solution
The equation you've provided seems to be a bit unclear. However, if you're asking to solve the equation in the form of 2^(2x - 4) = 8^(42), here's how you can solve it:
First, you need to express 8 as a power of 2, since 8 = 2^3. So, the equation becomes:
2^(2x - 4) = (2^3)^42
Simplify the right side of the equation using the rule of exponents (a^(m*n) = (a^m)^n):
2^(2x - 4) = 2^(3*42)
Now, you have the same base (2) on both sides of the equation, so you can set the exponents equal to each other:
2x - 4 = 3*42
Solve for x:
2x = 3*42 + 4
x = (3*42 + 4) / 2
So, that's the solution for x.
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