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Solve for x:2, start superscript, 2, x, minus, 4, end superscript, equals, 8, to the power 42 2x−4 =8 4

Question

Solve for x:2, start superscript, 2, x, minus, 4, end superscript, equals, 8, to the power 42 2x−4 =8 4

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Solution

The equation you've provided seems to be a bit unclear. However, if you're asking to solve the equation in the form of 2^(2x - 4) = 8^(42), here's how you can solve it:

First, you need to express 8 as a power of 2, since 8 = 2^3. So, the equation becomes:

2^(2x - 4) = (2^3)^42

Simplify the right side of the equation using the rule of exponents (a^(m*n) = (a^m)^n):

2^(2x - 4) = 2^(3*42)

Now, you have the same base (2) on both sides of the equation, so you can set the exponents equal to each other:

2x - 4 = 3*42

Solve for x:

2x = 3*42 + 4

x = (3*42 + 4) / 2

So, that's the solution for x.

This problem has been solved

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