The diameter of a field of view is 4.7mm. 4 cells fit across the diameter under 4x objective magnification.What is the actual size of each cell?2019 Atomi QuestionA(Choice A)2.94μmB(Choice B)29.4μmC(Choice C)0.0294μmD(Choice D)0.294μm

x40 objective lens and estimated the field of view to be 480 um. The student also estimated that 12 cells of this specimen fit across the field of view. The student completed a scientific drawing of one of the cells, and the drawing of the cell measured 16 cm in length.What is the size of each cell in um?

A student's microscope has an ocular lens with a 10x magnification. Calculate the total magnification, if the objective lens is set to 30x. 3x30x40x300x

A scientist observed a skin cell using an electron microscope.The size of the image was 25 mm, and the magnification was × 100,000.Calculate the real size of the cell, giving your answer in nm.

25. A particular compound microscope, with the 43x objective in position, has a diameter of thefield of view of approximately 0.31 mm and an area of approximately 0.1 mm2. The diameter of thefield of view is inversely proportional to the magnification of the objective. Counting left to rightone observes 15 rectangular onion epidermal cells across the field of view with the 43x objective inplace. Counting from top to bottom it can be observed that four cells span the diameter of the field.Using the 43x objective, one sees an average of 12 stomates per field of view. What is the bestestimate of the density of stomates per sq mm of epidermal surface?A. 12B. 15C. 36D. 120E. 150

Magnification can be calculated using the equation: magnification = size of image / actual size of the specimen. A bacterial cell is 0.003mm long. A magnified image of the cell is 21mm long. The magnification of the image is ×_____.