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Ice cubes of a total mass 80 g, and at 0 0C, are put into a chocolate drink of mass 275 g. All the icemelts as 25300 J of thermal energy transfers from the chocolate drink to the ice. The finaltemperature of the drink is 0 0C.(i) Calculate the specific latent heat of fusion for ice.

Question

Ice cubes of a total mass 80 g, and at 0 0C, are put into a chocolate drink of mass 275 g. All the icemelts as 25300 J of thermal energy transfers from the chocolate drink to the ice. The finaltemperature of the drink is 0 0C.(i) Calculate the specific latent heat of fusion for ice.

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Solution

The specific latent heat of fusion for a substance can be calculated using the formula:

L = Q / m

where: L is the specific latent heat, Q is the heat absorbed or released during the process, and m is the mass of the substance.

In this case, the heat (Q) is given as 25300 J and the mass (m) of the ice is given as 80 g.

So, substituting these values into the formula gives:

L = 25300 J / 80 g = 316.25 J/g

Therefore, the specific latent heat of fusion for ice in this case is 316.25 J/g.

This problem has been solved

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