What is the output of the following code snippet?#include<stdio.h>int main(){ int i = 5; int a = --i + --i; printf("%d",a); return 0;}a.8b.6c.5d.7
Question
What is the output of the following code snippet?#include<stdio.h>int main(){ int i = 5; int a = --i + --i; printf("%d",a); return 0;}a.8b.6c.5d.7
Solution
The output of this code is undefined. This is because the order of evaluation of the operands of the '+' operator is not specified in the C language. The '--' operator has a side effect of changing the value of 'i', and since the order of evaluation is not specified, we cannot know for sure what the final value of 'a' will be. It could be 8, 6, or some other value, depending on the compiler and the specific implementation. Therefore, none of the options a.8, b.6, c.5, d.7 can be definitively correct.
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