To solve this problem, we need to use the formula for compound interest, which is also applicable to population growth. The formula is:

A = P(1 + r/n)^(nt)

Where:
A = the amount of money accumulated after n years, including interest.
P = the principal amount (the initial amount of money)
r = annual interest rate (decimal)
n = number of times that interest is compounded per year
t = time the money is invested for in years

In this case, we are looking for A, the future population. P is the current population, which is 9,520 pigeons. The rate of increase r is 10% or 0.10 in decimal form. The population increases once per year, so n is 1. And we are looking for the population in 13 years, so t is 13.

Substituting these values into the formula, we get:

A = 9520(1 + 0.10/1)^(1*13)

Solving the equation:

A = 9520(1.10)^13

A = 9520 * 3.363

A = 31991.36

Rounding to the nearest whole number, we get 31991 pigeons. So, there will be approximately 31991 pigeons in Winchester in 13 years if the population continues to increase at a rate of 10% per year.

Question

To solve this problem, we need to use the formula for compound interest, which is also applicable to population growth. The formula is:

A = P(1 + r/n)^(nt)

Where:
A = the amount of money accumulated after n years, including interest.
P = the principal amount (the initial amount of money)
r = annual interest rate (decimal)
n = number of times that interest is compounded per year
t = time the money is invested for in years

In this case, we are looking for A, the future population. P is the current population, which is 9,520 pigeons. The rate of increase r is 10% or 0.10 in decimal form. The population increases once per year, so n is 1. And we are looking for the population in 13 years, so t is 13.

Substituting these values into the formula, we get:

A = 9520(1 + 0.10/1)^(1*13)

Solving the equation:

A = 9520(1.10)^13

A = 9520 * 3.363

A = 31991.36

Rounding to the nearest whole number, we get 31991 pigeons. So, there will be approximately 31991 pigeons in Winchester in 13 years if the population continues to increase at a rate of 10% per year.

Knowee AI · Accepted Answer

To solve this problem, we need to use the formula for compound interest, which is also applicable to population growth. The formula is:

A = P(1 + r/n)^(nt)

Where:
A = the amount of money accumulated after n years, including interest.
P = the principal amount (the initial amount of money)
r = annual interest rate (decimal)
n = number of times that interest is compounded per year
t = time the money is invested for in years

In this case, we are looking for A, the future population. P is the current population, which is 9,520 pigeons. The rate of increase r is 10% or 0.10 in decimal form. The population increases once per year, so n is 1. And we are looking for the population in 13 years, so t is 13.

Substituting these values into the formula, we get:

A = 9520(1 + 0.10/1)^(1*13)

Solving the equation:

A = 9520(1.10)^13

A = 9520 * 3.363

A = 31991.36

Rounding to the nearest whole number, we get 31991 pigeons. So, there will be approximately 31991 pigeons in Winchester in 13 years if the population continues to increase at a rate of 10% per year.

Despite control measures, the pigeon population in Winchester is increasing by 10% each year. If there are currently 9,520 pigeons, how many pigeons will there be in 13 years?If necessary, round your answer to the nearest whole number. pigeons

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