A hash table contains 10 buckets and uses linear probing to resolve collisions. The key values are integers and the hash function used is key % 10. If the values 43, 165, 62, 123, 142 are inserted in the table, in what location would the key value 142 be inserted?
Question
A hash table contains 10 buckets and uses linear probing to resolve collisions. The key values are integers and the hash function used is key % 10. If the values 43, 165, 62, 123, 142 are inserted in the table, in what location would the key value 142 be inserted?
Solution
To find the location where the key value 142 would be inserted, we first need to apply the hash function to the key. The hash function is key % 10.
Step 1: Apply the hash function to the key 142. 142 % 10 = 2
So, the hash function suggests that the key 142 should be inserted at location 2.
Step 2: Check if location 2 is empty. The values 43, 165, 62, 123 have already been inserted. Applying the hash function to these values:
43 % 10 = 3 165 % 10 = 5 62 % 10 = 2 123 % 10 = 3
The key 62 is already at location 2 and 43 and 123 have caused a collision at location 3.
Step 3: Resolve the collision using linear probing. Linear probing works by checking the next available spot in the hash table. Since location 2 and 3 are occupied, we check location 4.
Step 4: Insert the key 142 at the first available location found in step 3. So, the key 142 would be inserted at location 4.
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Sindhu is working on implementing a hash table with linear probing to efficiently store a set of unique integer keys. She is seeking your help to develop a program that accomplishes this.Your task is to write a program that takes a series of integers as input, hashes them into a hash table, resolves any collisions using linear probing, and then displays the keys and their corresponding indices in ascending order of their original insertion.ExampleInput 5514 16 17 26 10Output index: 0, value: 10index: 1, value: 16index: 2, value: 17index: 3, value: 26index: 4, value: 14ExplanationThe keys are inserted into the hash table division method using linear probing to resolve any collisions.Key 14 is inserted at index 4.Key 16 is inserted at index 1.Key 17 is inserted at index 2.Key 26 initially collides with index 1 but is inserted at the next available slot, which is index 3, using linear probing.Key 10 is inserted at index 0.The keys and their respective indices are sorted in ascending order of their original insertion.Input format :The first line of input consists of an integer size, which represents the size of the hash table.The second line of input consists of an integer n, which represents the number of keys to be inserted.The third line of input consists of n integers separated by a space, representing the keys to be inserted.Output format :For each key, the output displays a line with the following format: "index: [index], value: [value]".where [index] is the index in the hash table in ascending order, where the key is stored after resolving collisions, and [value] is the corresponding key value.Refer to the sample output for the formatting specifications.Code constraints :The test cases will fall under the following constraints:1 ≤ size ≤ 101 ≤ n ≤ 101 ≤ keys ≤ 100Sample test cases :Input 1 :5514 16 17 26 10Output 1 :index: 0, value: 10index: 1, value: 16index: 2, value: 17index: 3, value: 26index: 4, value: 14Input 2 :10510 43 68 90 13Output 2 :index: 0, value: 10index: 1, value: 90index: 3, value: 43index: 4, value: 13index: 8, value: 68
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