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10. Which of the following programming structures does not logically agree with the others?a) m=n>r<x;b) m=n!=x;c) m=n*x;d) m=n>=x

Question

  1. Which of the following programming structures does not logically agree with the others?a) m=n>r<x;b) m=n!=x;c) m=n*x;d) m=n>=x
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Solution

The answer is b) m=n!=x;

Here's why:

a) m=n>r<x; This is a logical comparison where n is greater than r and less than x, and the result is assigned to m.

b) m=n!=x; This is a logical comparison where n is not equal to x, and the result is assigned to m. However, the structure is different from the others because it doesn't involve a comparison between three variables.

c) m=n*x; This is a mathematical operation where n is multiplied by x, and the result is assigned to m.

d) m=n>=x; This is a logical comparison where n is greater than or equal to x, and the result is assigned to m.

So, option b) m=n!=x; is the one that does not logically agree with the others.

This problem has been solved

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