10. Which of the following programming structures does not logically agree with the others?a) m=n>r<x;b) m=n!=x;c) m=n*x;d) m=n>=x
Question
- Which of the following programming structures does not logically agree with the others?a) m=n>r<x;b) m=n!=x;c) m=n*x;d) m=n>=x
Solution
The answer is b) m=n!=x;
Here's why:
a) m=n>r<x; This is a logical comparison where n is greater than r and less than x, and the result is assigned to m.
b) m=n!=x; This is a logical comparison where n is not equal to x, and the result is assigned to m. However, the structure is different from the others because it doesn't involve a comparison between three variables.
c) m=n*x; This is a mathematical operation where n is multiplied by x, and the result is assigned to m.
d) m=n>=x; This is a logical comparison where n is greater than or equal to x, and the result is assigned to m.
So, option b) m=n!=x; is the one that does not logically agree with the others.
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