#include <iostream>using namespace std;class Base { public: Base() { cout << "Base Constructor" << endl; } }; class Derived : public Base { public: Derived() { cout << "Derived Constructor" << endl; } }; int main() { Derived d; return 0; }
Question
#include <iostream>using namespace std;class Base { public: Base() { cout << "Base Constructor" << endl; } }; class Derived : public Base { public: Derived() { cout << "Derived Constructor" << endl; } }; int main() { Derived d; return 0; }
Solution
The code you've posted is written in C++. It defines two classes, Base and Derived. Derived is a subclass of Base.
Here's a step-by-step explanation of what the code does:
-
The
Baseclass is defined with a constructor that prints "Base Constructor" when an object of theBaseclass is created. -
The
Derivedclass is defined as a subclass of theBaseclass. It has a constructor that prints "Derived Constructor" when an object of theDerivedclass is created. -
In the
mainfunction, an objectdof theDerivedclass is created. -
When
dis created, first theBaseconstructor is called (becauseDerivedis a subclass ofBase), printing "Base Constructor". Then, theDerivedconstructor is called, printing "Derived Constructor".
So, the output of this program will be:
Base Constructor
Derived Constructor
This is because when a derived class object is created, first the base class constructor is called, then the derived class constructor.
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