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#include <iostream>using namespace std;class Base {     public:         Base() {            cout << "Base Constructor" << endl;         } }; class Derived : public Base {     public:     Derived() {         cout << "Derived Constructor" << endl;     } }; int main() {     Derived d;     return 0; }

Question

#include <iostream>using namespace std;class Base {     public:         Base() {            cout << "Base Constructor" << endl;         } }; class Derived : public Base {     public:     Derived() {         cout << "Derived Constructor" << endl;     } }; int main() {     Derived d;     return 0; }

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Solution

The code you've posted is written in C++. It defines two classes, Base and Derived. Derived is a subclass of Base.

Here's a step-by-step explanation of what the code does:

  1. The Base class is defined with a constructor that prints "Base Constructor" when an object of the Base class is created.

  2. The Derived class is defined as a subclass of the Base class. It has a constructor that prints "Derived Constructor" when an object of the Derived class is created.

  3. In the main function, an object d of the Derived class is created.

  4. When d is created, first the Base constructor is called (because Derived is a subclass of Base), printing "Base Constructor". Then, the Derived constructor is called, printing "Derived Constructor".

So, the output of this program will be:

Base Constructor
Derived Constructor

This is because when a derived class object is created, first the base class constructor is called, then the derived class constructor.

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