According to Coulomb's law, a pair of charged particles that are placed at half a distance will experience forces that areGroup of answer choicesone quarter as strong.twice as strong.half as strong.four times as strong.
Question
According to Coulomb's law, a pair of charged particles that are placed at half a distance will experience forces that areGroup of answer choicesone quarter as strong.twice as strong.half as strong.four times as strong.
Solution
According to Coulomb's law, the force between two charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. This is mathematically expressed as F = k * q1 * q2 / r^2, where F is the force, k is Coulomb's constant, q1 and q2 are the amounts of charge, and r is the distance between the charges.
If the distance (r) is halved, then the new force (F') can be found by substitifying r/2 into the equation in place of r. This gives F' = k * q1 * q2 / (r/2)^2 = k * q1 * q2 / (r^2/4) = 4 * k * q1 * q2 / r^2 = 4F.
So, if the distance between the charges is halved, the force between them becomes four times as strong.
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