Factorise.128j2–242

The expression you've given is "128j^2 - 242". To factorise this, we first look for the greatest common factor (GCF). In this case, the GCF is 2. So, we can rewrite the expression as:

2(64j^2 - 121)

Now, we notice that both 64j^2 and 121 are perfect squares. So, we can factorise further:

2[(8j)^2 - (11)^2]

This is a difference of squares, which can be factorised as follows:

2(8j - 11)(8j + 11)

So, the factorised form of the expression "128j^2 - 242" is 2(8j - 11)(8j + 11).

The expression you've given is "128j^2 - 242". To factorise this, we first look for the greatest common factor (GCF). In this case, the GCF is 2. So, we can rewrite the expression as:

2(64j^2 - 121)

Now, we can see that both 64j^2 and 121 are perfect squares. So, we can factorise further:

2[(8j)^2 - (11)^2]

This is a difference of squares, which can be factorised as follows:

2(8j - 11)(8j + 11)

So, the factorised form of the expression "128j^2 - 242" is 2(8j - 11)(8j + 11).