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elect the correct answerWhat will be the output of the following code?class Node:    def __init__(self, data=None):        self.data = data        self.next = Noneclass LinkedList:    def __init__(self):        self.head = None    def print_list(self):        current_node = self.head        while current_node:            print(current_node.data)            current_node = current_node.nextllist = LinkedList()llist.head = Node(1)second = Node(2)third = Node(3)llist.head.next = secondsecond.next = thirdllist.print_list()Options1 2 31 3 22 3 13 2 1

Question

elect the correct answerWhat will be the output of the following code?class Node:    def init(self, data=None):        self.data = data        self.next = Noneclass LinkedList:    def init(self):        self.head = None    def print_list(self):        current_node = self.head        while current_node:            print(current_node.data)            current_node = current_node.nextllist = LinkedList()llist.head = Node(1)second = Node(2)third = Node(3)llist.head.next = secondsecond.next = thirdllist.print_list()Options1 2 31 3 22 3 13 2 1

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Solution

The correct answer is 1 2 3.

Here's the step by step explanation:

  1. A linked list is created with the head node being 1 (llist.head = Node(1)).
  2. A second node is created with the value 2 (second = Node(2)).
  3. A third node is created with the value 3 (third = Node(3)).
  4. The next node after the head (1) is set to the second node (2) (llist.head.next = second).
  5. The next node after the second node (2) is set to the third node (3) (second.next = third).
  6. The print_list method is called, which prints the data of each node in the list from the head to the end. Since the nodes are linked in the order 1 -> 2 -> 3, the output will be 1 2 3.

This problem has been solved

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