You are using the following code snippet in your application when working with Lists in Java.CodeList list = Arrays.asList(1, 2, 3, 4;list.forEach(i -> {i *= 2; System.out.print(i)});What will be the result of executing the code snippet?
Question
You are using the following code snippet in your application when working with Lists in Java.CodeList list = Arrays.asList(1, 2, 3, 4;list.forEach(i -> {i *= 2; System.out.print(i)});What will be the result of executing the code snippet?
Solution
The code snippet you provided will not compile in Java. The reason is that you are trying to modify a variable (i) inside a lambda expression, which is not allowed in Java. Variables used inside a lambda expression must be effectively final or actually final.
Here is the corrected version of your code:
List<Integer> list = Arrays.asList(1, 2, 3, 4);
list.stream().map(i -> i * 2).forEach(i -> System.out.print(i + " "));
This code will create a stream from the list, then map each element to its double value, and finally print each doubled value. The output will be:
2 4 6 8
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