How many such pair(s) of digits are there in the number ‘48240866’ which have as many digits between them as in the numerical series?

To solve this problem, we need to compare the number '48240866' with the numerical series (0-9). We are looking for pairs of digits that have the same number of digits between them in both the given number and the numerical series.

Let's break it down:

1. Start from the first digit of the number '48240866', which is 4. The next digit is 8. In the numerical series, there are 3 digits (5, 6, 7) between 4 and 8. But in the number '48240866', there are no digits between 4 and 8. So, this pair doesn't meet the condition.

2. Move to the next pair (8, 2). In the numerical series, there are 5 digits (3, 4, 5, 6, 7) between 2 and 8. But in the number '48240866', there are no digits between 8 and 2. So, this pair doesn't meet the condition either.

3. Continue this process for all pairs in the number '48240866'.

4. When you reach the pair (2, 4), you'll find that there is 1 digit (3) between 2 and 4 in the numerical series. In the number '48240866', there is also 1 digit (0) between 2 and 4. So, this pair meets the condition.

5. The pair (0, 8) also meets the condition as there are 7 digits (1, 2, 3, 4, 5, 6, 7) between 0 and 8 in the numerical series, and there are also 7 digits (4, 2, 4, 0, 8, 6, 6) between 0 and 8 in the number '48240866'.

6. The pair (8, 6) meets the condition as well, as there is 1 digit (7) between 8 and 6 in the numerical series, and there is also 1 digit (6) between 8 and 6 in the number '48240866'.

So, there are 3 pairs (2, 4), (0, 8), and (8, 6) in the number '48240866' that have as many digits between them as in the numerical series.

To solve this problem, we need to compare the number '48240866' with the numerical series (which is usually considered as '1234567890') and find pairs of digits that have the same number of digits between them in both the number and the numerical series.

Step 1: Write down the number and the numerical series for easy comparison.

Number: 48240866 Numerical series: 1234567890

Step 2: Start comparing each pair of digits in the number with the numerical series.

• The first pair in the number is '48'. In the numerical series, there is one digit between '4' and '8'. But in the number, there are no digits between '4' and '8'. So, this pair does not meet the condition.

• The second pair is '82'. In the numerical series, there are three digits between '8' and '2'. But in the number, there are no digits between '8' and '2'. So, this pair does not meet the condition.

• The third pair is '24'. In the numerical series, there are no digits between '2' and '4'. But in the number, there are two digits between '2' and '4'. So, this pair does not meet the condition.

• The fourth pair is '40'. In the numerical series, there are three digits between '4' and '0'. But in the number, there is one digit between '4' and '0'. So, this pair does not meet the condition.

• The fifth pair is '08'. In the numerical series, there is one digit between '0' and '8'. But in the number, there are no digits between '0' and '8'. So, this pair does not meet the condition.

• The sixth pair is '86'. In the numerical series, there are no digits between '8' and '6'. But in the number, there is one digit between '8' and '6'. So, this pair does not meet the condition.

• The seventh pair is '66'. In the numerical series, there are no digits between '6' and '6'. In the number, there are no digits between '6' and '6'. So, this pair meets the condition.

Step 3: Count the number of pairs that meet the condition.

There is only one pair ('66') that meets the condition.

So, the answer is 1. There is only one such pair of digits in the number '48240866' which have as many digits between them as in the numerical series.