The result of `printf("%d", 1 && 2);` will be `1`.

Here's why:

In C programming language, the `&&` operator is a logical AND operator. It returns true if both operands are true. In this case, the operands are `1` and `2`.

In C, any non-zero value is considered as `true`. So, both `1` and `2` are `true`.

Therefore, `1 && 2` is `true`. When you print a `true` value with `%d` format specifier, it prints `1`. So, the output will be `1`.

Question

The result of `printf("%d", 1 && 2);` will be `1`.

Here's why:

In C programming language, the `&&` operator is a logical AND operator. It returns true if both operands are true. In this case, the operands are `1` and `2`.

In C, any non-zero value is considered as `true`. So, both `1` and `2` are `true`.

Therefore, `1 && 2` is `true`. When you print a `true` value with `%d` format specifier, it prints `1`. So, the output will be `1`.

Knowee AI · Accepted Answer

The result of `printf("%d", 1 && 2);` will be `1`.

Here's why:

In C programming language, the `&&` operator is a logical AND operator. It returns true if both operands are true. In this case, the operands are `1` and `2`.

In C, any non-zero value is considered as `true`. So, both `1` and `2` are `true`.

Therefore, `1 && 2` is `true`. When you print a `true` value with `%d` format specifier, it prints `1`. So, the output will be `1`.

What is the result of printf("%d", 1 && 2);?

Question

Solution

Similar Questions

Upgrade your grade with Knowee