A ball is thrown vertically upwards with a velocity of 49 m/s and g =9.8 m/s2Calculate the max height it rises up to?112.5 m
Question
A ball is thrown vertically upwards with a velocity of 49 m/s and g =9.8 m/s2Calculate the max height it rises up to?112.5 m
Solution
Sure, I can help with that. The maximum height a ball reaches when thrown vertically upwards can be calculated using the following formula from physics:
h = (v^2) / (2g)
where:
- h is the maximum height,
- v is the initial velocity, and
- g is the acceleration due to gravity.
Given that the initial velocity v is 49 m/s and the acceleration due to gravity g is 9.8 m/s^2, we can substitute these values into the formula:
h = (49 m/s)^2 / (2 * 9.8 m/s^2) = 122.5 m
So, the ball will rise up to a maximum height of 122.5 meters.
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