What is the result of this code?ArrayList<String> flowers = new ArrayList<>();flowers.add("daisy");flowers.add("rose");flowers.add("orchid");System.out.println(flowers.get(3));System.out.println(flowers.get(2));System.out.println(flowers.get(1));a.)<Exception error...>b.)orchidrosedaisyc.)321d.)daisyroseorchid
Question
What is the result of this code?ArrayList<String> flowers = new ArrayList<>();flowers.add("daisy");flowers.add("rose");flowers.add("orchid");System.out.println(flowers.get(3));System.out.println(flowers.get(2));System.out.println(flowers.get(1));a.)<Exception error...>b.)orchidrosedaisyc.)321d.)daisyroseorchid
Solution
The result of this code would be an exception error. In Java, ArrayList indices start at 0, not 1. So when you try to access the element at index 3 with flowers.get(3), it will throw an IndexOutOfBoundsException because there is no element at index 3. The elements are at indices 0, 1, and 2. So the correct answer is a.) <Exception error...>.
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