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To rent a certain meeting room, a college charges a reservation fee of $42 and an additional fee of $7.30 per hour. The math club wants to spend less than $71.20 on renting the meeting room.What are the possible amounts of time for which they could rent the meeting room?Use t for the number of hours the meeting room is rented, and solve your inequality for t.

Question

To rent a certain meeting room, a college charges a reservation fee of 42andanadditionalfeeof42 and an additional fee of 7.30 per hour. The math club wants to spend less than $71.20 on renting the meeting room.What are the possible amounts of time for which they could rent the meeting room?Use t for the number of hours the meeting room is rented, and solve your inequality for t.

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Solution

The total cost of renting the meeting room is given by the equation:

Cost = Reservation fee + (Hourly fee * Number of hours) Cost = 42+42 + 7.30t

The math club wants to spend less than $71.20, so we set up the inequality:

42+42 + 7.30t < $71.20

To solve for t, we first subtract $42 from both sides:

7.30t<7.30t < 71.20 - 4242 7.30t < $29.20

Then, we divide both sides by $7.30 to isolate t:

t < 29.20/29.20 / 7.30 t < 4 hours

So, the math club could rent the meeting room for less than 4 hours.

This problem has been solved

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