According to the following equation:The value of constant ‘A’ for a given solvent and temperature is same forNaCl and CaCl2NaCl and MgSO4CaCl2 and MgSO4CaCl2 and Mg(OH)2
Question
According to the following equation:The value of constant ‘A’ for a given solvent and temperature is same forNaCl and CaCl2NaCl and MgSO4CaCl2 and MgSO4CaCl2 and Mg(OH)2
Solution
The question seems to be incomplete. It mentions an equation and a constant 'A' but does not provide the actual equation or any context about what 'A' represents. In order to provide an accurate answer, the full equation and more information about 'A' is needed.
In general, if 'A' is a constant related to a specific solvent and temperature, it could potentially be the same for different solutes (like NaCl, CaCl2, MgSO4, Mg(OH)2) if it does not depend on the nature of the solute. However, without the specific equation or context, it's impossible to give a definitive answer.
Similar Questions
According to the following equation:The value of constant ‘A’ for a given solvent and temperature is same for
What is the value of x when 32.2 g of Na2SO4•xH2O are heated leaving 14.2 g of anhydrous Na2SO4? Mr(H2O) = 18; Mr(Na2SO4) = 142.Na2SO4•xH2O (s) → Na2SO4 (s) + xH2O (g)A. 0.1B. 1C. 5D. 10
The freezing point depression constant for water is 1.86 °C kg/mol. How much would the freezing point of water be depressed when 0.75 moles of calcium chloride (CaCl₂) is dissolved in 500 grams of water?Select one:a.0.372 °Cb.0.186 °Cc.0.558 °Cd.1.860 °C
Which of the following is correctly matched(at constant temperature) :-(where a = initial concentration)(1) t × a = constant, for 2 order kinetics(2) t × a = constant, for I order kinetics(3) t × a = constant, for zero order kinetics(4) Unit of rate constant is M sec for I order
For the reaction, A + B⇌C + D, the initial concentration of ‘A’ and ‘B’ are equal, but the equilibrium concentration of ‘C’ is twice that of equilibrium concentration of ‘A’. Theequilibrium constant is _______
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.